400V 100uf capacitor You charge voltage is 50V, then the final capacitor at both ends of the voltage is 50V, not 400V, but 50V10uf capacitor can not be charged 400V, because the voltage range has far exceeded the voltage, will breakdown the capacitor, can you understand
A capacitor, if with 1 library of electricity when the potential difference between the two stages is 1 volt, the capacitance of this capacitor is 1 method, that is: C=Q\/U
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2, but the size of the capacitor is not determined by Q (with electricity) or U (voltage), that is: C=εS\/4πkd. Where ε is a constant, S is the opposite area of the capacitor plate, d is the distance of the capacitor plate, and k is the electrostatic constant. For common parallel plate capacitors, the capacitance is C=εS\/d. (ε is the dielectric constant of the medium between plates, S is the plate area, and d is the distance between plates.)
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3, the capacitor potential energy calculation formula: E=CU^2\/2=QU\/2
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4, multi-capacitor parallel calculation formula: C=C1 C2 C3... Cn multi-capacitor series calculation formula: 1\/C=1\/C1 1\/C2... 1\/Cn
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5, the capacitor for high frequency AC obstruction effect is reduced, that is, the capacitive reactance is small, whereas the capacitor for low frequency AC generated by the capacitive reactance is large; For the same frequency of AC electricity. The larger the capacity of the capacitor, the smaller the capacitive reactance, and the smaller the capacity, the greater the capacitive reactance
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6, series voltage division ratio: the larger the capacitor, the smaller the voltage. Parallel shunt ratio: the larger the capacitor, the larger the current
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7, when t= RC, capacitance voltage =0.63E; When t= 2RC, the capacitance voltage is 0.86E; When t= 3RC, capacitance voltage =0.95E; When t= 4RC, capacitance voltage =0.98E; When t= 5RC, capacitance voltage =0.99E; T units, S units, R units, ohms, C units, F units
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8, T time voltage: Vt=V0 (V1-V0)*[1-exp(-t\/RC)]